A free quadratic equation calculator that shows and explains each step in solving your quadratic equation.

You entered:

There are no solutions in the real number domain.

There are two complex solutions: x = 1.1857142857143 + 0.55530833501648

where

(1)

For any quadratic equation

(2)

In the form above, you specified values for the variables a, b, and c. Plugging those values into Eqn. 1, we get:

(3) \(x=--83\pm\frac{\sqrt{-83^2-4*35*60}}{2*35}\)

which simplifies to:

(4) \(x=--83\pm\frac{\sqrt{6889-8400}}{70}\)

(5) \(x=--83\pm\frac{\sqrt{-1511}}{70}\)

This means that our solution will require finding the square root of a negative number. There is no real number solution for this, so our solution will be a complex number (that is, it will involve the imaginary number

Let's calculate the square root:

(6) \(x=--83\pm\frac{38.871583451154i}{70}\)

This equation further simplifies to:

(7) \(x=-\frac{--83}{70}\pm0.55530833501648i\)

Solving for x, we find two solutions which are both complex numbers:

x = 1.1857142857143 + 0.55530833501648

and

x = 1.1857142857143 - 0.55530833501648

Both of these solutions are complex numbers.

These are the two solutions that will satisfy the equation

ax

\ In this equation, x is an unknown. A, b, and c are constants. A and b are referred to as coefficients. It should be noted that a cannot equal zero. If a=0, then ax

Calculating a solution to a quadratic equation may appear challenging. However, you have this handy-dandy quadratic equation calculator. All kidding aside, quadratic equations can be quickly solved using the quadratic formula, which is the same technique used by this quadratic equation calculator. Try it, and it will explain each of the steps to you. The quadratic formula is written:

Since there are always 2 solutions to a square root (one negative, one positive), solving the quadratic equation results in 2 values for x. The two solutions for x (which may be positive or negative, real or complex) are called roots. Rarely, these two roots may be the same, meaning there will only be one solution for x.

Who cares? Why do we care about qudratic equations? Quadratic equations are needed to calculate answers to many real-world problems. The contour of a parablolic mirror is one example of an application of quadratic equations.

As mentioned above, in the equation ax

We this quadratic equation calculator is useful to you. We encourage you to try it with different values, and to read the explanation for how to reach your answer. But, if you just want to use it to calculate the answers to your quadratic equations, that's cool too. Thank you for using Quadratic-Equation-Calculator.com.

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