A free quadratic equation calculator that shows and explains each step in solving your quadratic equation.

You entered:

There are no solutions in the real number domain.

There are two complex solutions: x = -0.21951219512195 + 0.62517100575494

where

(1)

For any quadratic equation

(2)

In the form above, you specified values for the variables a, b, and c. Plugging those values into Eqn. 1, we get:

(3) \(x=-18\pm\frac{\sqrt{18^2-4*41*18}}{2*41}\)

which simplifies to:

(4) \(x=-18\pm\frac{\sqrt{324-2952}}{82}\)

(5) \(x=-18\pm\frac{\sqrt{-2628}}{82}\)

This means that our solution will require finding the square root of a negative number. There is no real number solution for this, so our solution will be a complex number (that is, it will involve the imaginary number

Let's calculate the square root:

(6) \(x=-18\pm\frac{51.264022471905i}{82}\)

This equation further simplifies to:

(7) \(x=-\frac{-18}{82}\pm0.62517100575494i\)

Solving for x, we find two solutions which are both complex numbers:

x = -0.21951219512195 + 0.62517100575494

and

x = -0.21951219512195 - 0.62517100575494

Both of these solutions are complex numbers.

These are the two solutions that will satisfy the equation

Calculating a solution to a quadratic equation may appear daunting, because both x and x

Since there are always 2 solutions to a square root (one negative, one positive), solving the quadratic equation results in 2 values for x. The two solutions for x (which may be positive or negative, real or complex) are called roots. Depending on the values of a, b, and c, both roots may have the same value, meaning there will only be one solution for x.

Quadratic equations have real-life applications. Quadratic equations are needed to find answers in many real-world fields, including physics, pharmacokinetics and architecture.

In our equation, a cannot be zero. However, b can be zero, and so can c.

We hope you find this quadratic equation calculator useful. We encourage you to try it with different values, and to read the explanation for how to reach your answer. But we totally understand if you just want to use it to find the answers you're looking for. Thank you for using Quadratic-Equation-Calculator.com.

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